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Example 4 - Mayank made a bird-bath for his garden - Examples

  1. Chapter 13 Class 10 Surface Areas and Volumes
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Example 4 Mayank made a bird-bath for his garden in the shape of a cylinder with a hemispherical depression at one end (see figure). The height of the cylinder is 1.45 m and its radius is 30 cm. Find the total surface area of the bird-bath.(Take π = 22/7) Total surface area of the bird-bath = Curved Surface area of cylinder + Curved Surface area of hemisphere Curved Surface area of cylinder Curved Surface area of cylinder = 2𝜋𝑟ℎ Here, Height of the cylinder (h) = 1.45m = 1.45×100cm = 145 cm And radius = r = 30 cm Curved Surface area of cylinder = 2𝜋𝑟ℎ = 2×𝜋×30×145 = 8700 𝜋 Curved Surface area of hemisphere Here, radius = 30 cm Curved Surface area of hemisphere = 2𝜋𝑟2 = 2×𝜋×(30)^2 = 2×𝜋×30×30 = 2×𝜋×900 = 1800 𝜋 cm2 Now, Total surface area of the bird-bath = Curved Surface area of cylinder + Curved Surface area of hemisphere = 8700π + 1800π = 10500π = 10500 × 22/7 = 1500 × 22 = 33000 cm2 = 33000 × 1/100 × 1/100 m2 = 3.3 m2 Hence, surface area of the bird-bath = 3.3m2

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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