Ex 12.3

Ex 12.3, 1
Deleted for CBSE Board 2023 Exams

Ex 12.3, 2 Deleted for CBSE Board 2023 Exams You are here

Ex 12.3, 3 Deleted for CBSE Board 2023 Exams

Ex 12.3, 4 Important Deleted for CBSE Board 2023 Exams

Ex 12.3, 5 Deleted for CBSE Board 2023 Exams

Ex 12.3, 6 Deleted for CBSE Board 2023 Exams

Ex 12.3, 7 Deleted for CBSE Board 2023 Exams

Ex 12.3, 8 Important Deleted for CBSE Board 2023 Exams

Ex 12.3, 9 Deleted for CBSE Board 2023 Exams

Ex 12.3, 10 Deleted for CBSE Board 2023 Exams

Ex 12.3, 11 Deleted for CBSE Board 2023 Exams

Ex 12.3, 12 Important Deleted for CBSE Board 2023 Exams

Ex 12.3, 13 Important Deleted for CBSE Board 2023 Exams

Ex 12.3, 14 Deleted for CBSE Board 2023 Exams

Ex 12.3, 15 Important Deleted for CBSE Board 2023 Exams

Ex 12.3, 16 Important Deleted for CBSE Board 2023 Exams

Chapter 12 Class 10 Areas related to Circles

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 12.3, 2 Find the area of the shaded region in figure, if radii of the two concentric circles with centre O are 7 cm and 14 cm respectively and ∠AOC = 40°. Area of shaded region = Area of sector AOC – Area of sector BOD Area of sector BOD In smaller circle, θ = 40° and r = 7 cm Area of sector BOD = 𝜃/360×𝜋𝑟2 = 40/360×22/7×(7)2 = 1/9×22/7×7×7 = 1/9×22×7 = 154/9 cm2 Area of sector AOC In larger circle, θ=40° , r = 14 cm Area of sector AOC = 𝜃/(360°)×𝜋𝑟^2 = 40/360×22/7×(14)2 = 1/9×22/7×14×14 = 1/9×22×2×14 = 616/9 cm2 Now , Area of shaded region = Area of sector AOC – Area of sector BOD = 616/9−154/9 = (616−154)/9 = 462/9 = 154/3 cm2 Hence, area of shaded region = 154/3 cm2