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Ex 12.3
Ex 12.3, 2 Deleted for CBSE Board 2023 Exams
Ex 12.3, 3 Deleted for CBSE Board 2023 Exams
Ex 12.3, 4 Important Deleted for CBSE Board 2023 Exams
Ex 12.3, 5 Deleted for CBSE Board 2023 Exams
Ex 12.3, 6 Deleted for CBSE Board 2023 Exams
Ex 12.3, 7 Deleted for CBSE Board 2023 Exams
Ex 12.3, 8 Important Deleted for CBSE Board 2023 Exams
Ex 12.3, 9 Deleted for CBSE Board 2023 Exams
Ex 12.3, 10 Deleted for CBSE Board 2023 Exams
Ex 12.3, 11 Deleted for CBSE Board 2023 Exams
Ex 12.3, 12 Important Deleted for CBSE Board 2023 Exams
Ex 12.3, 13 Important Deleted for CBSE Board 2023 Exams
Ex 12.3, 14 Deleted for CBSE Board 2023 Exams You are here
Ex 12.3, 15 Important Deleted for CBSE Board 2023 Exams
Ex 12.3, 16 Important Deleted for CBSE Board 2023 Exams
Last updated at March 22, 2023 by Teachoo
Ex 12.3, 14 AB and CD are respectively arcs of two concentric circles of radii 21 cm and 7 cm and centre O (see figure). If AOB = 30 , find the area of the shaded region. Area of shaded region = Area of sector AOB Area of sector COD Area of sector AOB radius = r = 21 cm & = 30 Area of sector AOB = /360 r2 = 30/360 22/7 21 21 = 1/12 22 3 21 = 231/2 cm2 Area of sector COD radius = r = 7 cm & = 30 Area of sector COD = /360 r2 = (30 )/360 22/7 (7)2 = 1/12 22/7 7 7 = 77/6 cm2 Now , Area of shaded region = Area of Sector OAB Area of sector OCD = 231/2 77/6 = (3 231 77)/6 = (693 77)/6 = 616/6 = 308/3 cm2 Hence, area of shaded region = 308/3 cm2