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Chapter 6 Class 10 Triangles
Example 8 Important
Example 14 Important
Example 10 Important
Theorem 6.1 - Basic Proportionality Theorem (BPT) Important
Theorem 6.7 Important
Ex 6.2, 4 Important
Ex 6.2, 5 Important
Ex 6.2, 6 Important
Ex 6.2, 9 Important
Ex 6.3, 11 Important
Ex 6.3, 12 Important
Ex 6.3, 13 Important
Ex 6.3, 14 Important
Ex 6.3, 15 Important You are here
Ex 6.4, 1 Important
Ex 6.4, 3 Important
Ex 6.4, 5 Important
Ex 6.5, 2 Important
Ex 6.5, 3 Important
Ex 6.5, 8 Important
Ex 6.5, 11 Important
Ex 6.5, 12 Important
Ex 6.5, 15 Important
Chapter 6 Class 10 Triangles
Last updated at June 23, 2017 by Teachoo
Ex 6.3, 15 A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Given: Height of pole = AB = 6m Length of pole of shadow = BC = 4 m Length of shadow of tower = EF = 28 To Find : Height of tower i.e ED Solution:- In β π΄π΅πΆ and β π·πΈπΉ β B = β E = 90Β° β πΆ=β πΉ β΄ β π΄π΅πΆ βΌ β π·πΈπΉ β π΄π΅πΆ βΌ β π·πΈπΉ We know that if two triangles are similar, ratio of their sides are in proportion So, π΄π΅/π·πΈ=π΅πΆ/πΈπΉ 6/π·πΈ=4/28 6 Γ28=π·πΈΓ4 (6 Γ 28)/4= π·πΈ 6 Γ7=π·πΈ π·πΈ = 42 Hence, the height of the tower is 42 metres