Ex 6.3, 11 - E is a point on side CB produced of isosceles - AA Similarity

  1. Class 10
  2. Important Questions for Exam - Class 10
Ask Download

Transcript

Ex 6.3, 11 In figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that ΔABD ∼ ΔECF. Given: Isosceles triangle ABC Where , AB = AC And , AD ⊥ BC, EF ⊥ AC E is a point on side CB To Prove : ∆ 𝐴𝐵𝐷 ∼ ∆ 𝐸𝐶𝐹 Proof :- ∆ 𝐴𝐵𝐶 is isosceles triangle Where , AB = AC So, ∠𝐶=∠𝐵 In ∆ 𝐴𝐵𝐷 and ∆ 𝐸𝐶𝐹 ∠𝐴𝐵𝐷=∠𝐸𝐶𝐹 ∠𝐴𝐷𝐵=∠𝐸𝐹𝐶 Using AA similarity So, ∆ 𝐴𝐵𝐷 ∼ ∆ 𝐸𝐶𝐹 Hence proved

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.