

Introducing your new favourite teacher - Teachoo Black, at only βΉ83 per month
Chapter 6 Class 10 Triangles
Example 8 Important
Example 14 Important
Example 10 Important
Theorem 6.1 - Basic Proportionality Theorem (BPT) Important
Theorem 6.7 Important
Ex 6.2, 4 Important
Ex 6.2, 5 Important
Ex 6.2, 6 Important You are here
Ex 6.2, 9 Important
Ex 6.3, 11 Important
Ex 6.3, 12 Important
Ex 6.3, 13 Important
Ex 6.3, 14 Important
Ex 6.3, 15 Important
Ex 6.4, 1 Important
Ex 6.4, 3 Important
Ex 6.4, 5 Important
Ex 6.5, 2 Important
Ex 6.5, 3 Important
Ex 6.5, 8 Important
Ex 6.5, 11 Important
Ex 6.5, 12 Important
Ex 6.5, 15 Important
Chapter 6 Class 10 Triangles
Last updated at March 14, 2019 by Teachoo
Ex 6.2, 6 In figure, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show that BC || QR. Given: AB II PQ and AC II PR To prove: BC II QR Proof: In β πππ AB II PQ (Line drawn parallel to one side of triangle, intersects the other two sides in distinct points, Then it divides the other 2 side in same ratio) ππ΄/π΄π=ππ΅/π΅π In β πππ AC II PR (Line drawn parallel to one side of triangle, intersects the other two sides in distinct points, Then it divides the other 2 side in same ratio) ππΆ/πΆπ =ππ΄/π΄π From (1) & (2) ππΆ/πΆπ =ππ΅/π΅π Thus in Ξ OQR, ππΆ/πΆπ =ππ΅/π΅π i.e. Line BC divides the triangle Ξ OQR in the same ratio β΄ BC II QR (If a line divides any two sides of a triangles in the same ratio , then the line is parallel to the third side) Hence proved