1. Chapter 4 Class 10 Quadratic Equations (Term 2)
  2. Serial order wise
  3. Examples

Example 7 - Chapter 4 Class 10 Quadratic Equations (Term 2)

Last updated at May 29, 2018 by

Example 7 - Solve 2x2 - 5x + 3 = 0 by completing the square - Solving by completing square

Example 7 - Chapter 4 Class 10 Quadratic Equations - Part 2
Example 7 - Chapter 4 Class 10 Quadratic Equations - Part 3
Example 7 - Chapter 4 Class 10 Quadratic Equations - Part 4

  1. Chapter 4 Class 10 Quadratic Equations (Term 2)
  2. Serial order wise

    3. Examples

    Case Based Questions (MCQ) →

Transcript

Example 7 Solve the equation given in Example 3 (2x2 5x + 3 = 0) by the method of completing the square. 2x2 5x + 3 = 0 Dividing by 2 (2 2 5 + 3)/2=0/2 2 2/2 5 /2+3/2=0 x2 5 /2+3/2=0 We know that (a b)2 = a2 2ab + b2 Here, a = x & 2ab = ( 5 )/2 2xb = ( 5 )/2 2b = ( 5)/2 b = ( 5)/(2( 2)) b = 5/4 Now, in our equation x2 5 /2+3/2=0 Adding and subtracting (5/4)^2 x2 5 /2+3/2+(5/4)^2 (5/4)^2=0 x2 +(5/4)^2 5 /2+3/2 (5/4)^2=0 ( 5/4)^2 +3/2 (5/4)^2=0 ( 5/4)^2 +3/2 25/16=0 ( 5/4)^2=25/16 3/2 ( 5/4)^2=(25 3(8))/16 ( 5/4)^2=(25 24)/16 ( 5/4)^2=1/16 ( 5/4)^2=(1/4)^2 Cancelling square 5/4 = 1/4 5/4 = 1/4 Solving So, the roots of the equation are x = 3/2 & x = 1

Chapter 4 Class 10 Quadratic Equations (Term 2)
Serial order wise

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