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Example 1 (i) - Chapter 4 Class 10 Quadratic Equations (Term 2)
Last updated at July 29, 2021 by Teachoo
Examples
Example 1 (i)
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Example 1 (ii)
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Deleted for CBSE Board 2023 Exams
Example 8 Important Deleted for CBSE Board 2023 Exams
Example 9 Important Deleted for CBSE Board 2023 Exams
Example 10
Example 11
Example 12 Important
Example 13 (i)
Example 13 (ii) Important
Example 13 (iii)
Example 14 (i)
Example 14 (ii)
Example 15 Important
Example 16
Example 17 Important
Example 18
Chapter 4 Class 10 Quadratic Equations
Serial order wise
- Ex 4.1
- Ex 4.2
- Ex 4.3
- Ex 4.4
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Examples
- Case Based Questions (MCQ)
Transcript
Example 1 Represent the following situations mathematically: (i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with. Total number of marbles = 45 Let the number of marbles with John = x So, number of marbles with Jivanti = 45 – x marbles After losing 5 marbles, Number of marbles with John = x – 5 Number of marbles with Jivanti = 45 – x – 5 = 40 – x Given that Product of marbles now = 124 (x – 5) (40 – x) = 124 x (40 – x) – 5 (40 – x) = 124 40x – x2 – 200 + 5x = 124 45x – x2 – 200 = 124 0 = x2 + 200 – 45x + 124 0 = x2 – 45x + 324 x2 – 45x + 324 = 0 Hence, the required quadratic equation is x2 – 45x + 324 = 0
