Question 7 (ii) - Examples - Chapter 4 Class 10 Quadratic Equations

Last updated at April 16, 2024 by

Example 14 - Chapter 4 Class 10 Quadratic Equations - Part 3

Example 14 - Chapter 4 Class 10 Quadratic Equations - Part 4
Example 14 - Chapter 4 Class 10 Quadratic Equations - Part 5

Transcript

Example 14 Find the roots of the following equations: (ii) 1/𝑥−1/(𝑥−2)=3,𝑥≠0,2 1/𝑥−1/(𝑥 − 2)=3 ((𝑥 − 2) − 𝑥 )/(𝑥(𝑥 − 2))=3 (−2 )/(𝑥(𝑥 − 2))=3 –2 = 3x(x – 2) –2 = 3x2 – 6x 0 = 3x2 – 6x + 2 3x2 – 6x + 2 = 0 We solve this equation by quadratic formula 3x2 – 6x + 2 = 0 Comparing equation with ax2 + bx + c = 0 Here, a = 3, b = –6, c = 2 We know that D = b2 – 4ac D = (– 6)2 – 4×(3)×(2) D = 36 – 24 D = 12 So, the roots of the equation is given by x = (− 𝑏 ± √𝐷)/2𝑎 Putting values x = (−(− 6) ± √12)/(2 × 3) x = (6 ± √12)/6 x = (6 ± √(4 × 3))/6 x = (6 ± √(4 ) ×√3)/6 x = (6 ± 2 √3)/6 x = (2(3 ± √3))/(2 × 3) x = (3 ± √3)/3 So , the roots of the equation are (3 + √3)/3 and (3 − √3)/3

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.