Example 14 (ii) - Chapter 4 Class 10 Quadratic Equations (Term 2)
Last updated at Aug. 3, 2021 by Teachoo
Examples
Example 1 (i)
Important
Example 1 (ii)
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Deleted for CBSE Board 2022 Exams
Example 8 Important Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
Example 10
Example 11
Example 12 Important
Example 13 (i)
Example 13 (ii) Important
Example 13 (iii)
Example 14 (i)
Example 14 (ii) You are here
Example 15 Important
Example 16
Example 17 Important
Example 18
Chapter 4 Class 10 Quadratic Equations (Term 2)
Serial order wise
- Ex 4.1
- Ex 4.2
- Ex 4.3
- Ex 4.4
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Examples
- Case Based Questions (MCQ)
Transcript
Example 14 Find the roots of the following equations: (ii) 1/𝑥−1/(𝑥−2)=3,𝑥≠0,2 1/𝑥−1/(𝑥 − 2)=3 ((𝑥 − 2) − 𝑥 )/(𝑥(𝑥 − 2))=3 (−2 )/(𝑥(𝑥 − 2))=3 –2 = 3x(x – 2) –2 = 3x2 – 6x 0 = 3x2 – 6x + 2 3x2 – 6x + 2 = 0 We solve this equation by quadratic formula 3x2 – 6x + 2 = 0 Comparing equation with ax2 + bx + c = 0 Here, a = 3, b = –6, c = 2 We know that D = b2 – 4ac D = (– 6)2 – 4×(3)×(2) D = 36 – 24 D = 12 So, the roots of the equation is given by x = (− 𝑏 ± √𝐷)/2𝑎 Putting values x = (−(− 6) ± √12)/(2 × 3) x = (6 ± √12)/6 x = (6 ± √(4 × 3))/6 x = (6 ± √(4 ) ×√3)/6 x = (6 ± 2 √3)/6 x = (2(3 ± √3))/(2 × 3) x = (3 ± √3)/3 So , the roots of the equation are (3 + √3)/3 and (3 − √3)/3
