Example 13 (ii) - Chapter 4 Class 10 Quadratic Equations (Term 2)
Last updated at Aug. 3, 2021 by Teachoo
Transcript
Example 13 Find the roots of the following quadratic equations, if they exist, using the quadratic formula: (ii) x2 + 4x + 5 = 0 x2 + 4x + 5 = 0 Comparing equation with ax2 + bx + c = 0 Here, a = 1, b = 4, c = 5 We know that D = b2 4ac D = (4)2 4 (1) (5) D = (4)2 20 D = 16 20 D = 4 Hence roots to equation are x = ( )/2 x = ( 4 ( 4))/(2 (1)) Since there is a negative number in the root, therefore D will not have any real value. So, there are no real roots for the given equation.
Examples
Example 1 (i)
Important
Example 1 (ii)
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Deleted for CBSE Board 2022 Exams
Example 8 Important Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
Example 10
Example 11
Example 12 Important
Example 13 (i)
Example 13 (ii) Important You are here
Example 13 (iii)
Example 14 (i)
Example 14 (ii)
Example 15 Important
Example 16
Example 17 Important
Example 18
Chapter 4 Class 10 Quadratic Equations (Term 2)
Serial order wise
- Ex 4.1
- Ex 4.2
- Ex 4.3
- Ex 4.4
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Examples
- Case Based Questions (MCQ)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.