Example 4 - Chapter 4 Class 10 Quadratic Equations (Term 2)
Last updated at July 9, 2018 by Teachoo
Examples
Example 1 (i)
Important
Example 1 (ii)
Example 2 Important
Example 3
Example 4 You are here
Example 5 Important
Example 6
Example 7 Deleted for CBSE Board 2022 Exams
Example 8 Important Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
Example 10
Example 11
Example 12 Important
Example 13 (i)
Example 13 (ii) Important
Example 13 (iii)
Example 14 (i)
Example 14 (ii)
Example 15 Important
Example 16
Example 17 Important
Example 18
Chapter 4 Class 10 Quadratic Equations (Term 2)
Serial order wise
- Ex 4.1
- Ex 4.2
- Ex 4.3
- Ex 4.4
-
Examples
- Case Based Questions (MCQ)
Transcript
Example 4 Find the roots of the quadratic equation 6x2 – x – 2 = 0. 6x2 – x – 2 = 0 We factorize by splitting the middle term method We need to find two numbers whose Sum = -1 Product = -2 x 6 = -12 Checking -2 & 6, Sum = 4, Product = -12 Checking -4 & 3, Sum = -1, Product = -12 So, we take -4 and 3 6x2 – 4x + 3x – 2 = 0 2x (3x – 2) + 1 (3x – 2) = 0 (2x + 1) (3x – 2) = 0 2x + 1 =0 2x = -1 x = -1/2 3x - 2 = 0 3x = 2 x = 2/4 Hence x = (−1)/2 and x = 2/3 are the roots of the equation
