In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot 𝜃  equals

(a) 3/4  (b) 5/12   (c) 4/3   (d) 12/5

Ques 14 (MCQ) - In fig, AD=4cm,BD=3cm and CB=12 cm, then cot θ equals - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]

part 2 - Question 14 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 14 In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot 𝜃 equals (a) 3/4 (b) 5/12 (c) 4/3 (d) 12/5 To find cot θ, We need to find AB In right Δ ABD By Pythagoras theorem AB2 = AD2 + BD2 AB2 = 42 + 32 AB2 = 16 + 9 AB2 = 25 AB2 = 52 AB = 5 cm Now, tan 𝜃 = 𝐴𝐵/𝐵𝐶 tan 𝜃 = 5/12 Thus, cot 𝜃 = 𝟏𝟐/𝟓 So, the correct answer is (d)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo