Question 37 If the letters of the word RAMANUJAN are put in a box and one letter is drawn at random. The probability that the letter is A is (a) 3/5 (b) 1/2 (c) 3/7 (d) 1/3
The word word RAMANUJAN has
1 R, 3 A, 1 M, 2 N, 1 U, 1 J,
Total number of letters = 9
Number times A comes = 3
Thus,
Probability that the letter is A = (ππ’ππππ ππ π‘ππππ π΄ πππππ )/(πππ‘ππ ππ’ππππ ππ πππ‘π‘πππ )
= 3/9
= π/π
So, the correct answer is (d)
Made by
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.
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