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Β If the letters of the word RAMANUJAN are put in a box and one letter is drawn at random. The probability that the letter is A is

(a) 3/5Β  (b) 1/2Β  (c) 3/7 Β  (d) 1/3

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Question 37 If the letters of the word RAMANUJAN are put in a box and one letter is drawn at random. The probability that the letter is A is (a) 3/5 (b) 1/2 (c) 3/7 (d) 1/3 The word word RAMANUJAN has 1 R, 3 A, 1 M, 2 N, 1 U, 1 J, Total number of letters = 9 Number times A comes = 3 Thus, Probability that the letter is A = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘–π‘šπ‘’π‘  𝐴 π‘π‘œπ‘šπ‘’π‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘™π‘’π‘‘π‘‘π‘’π‘Ÿπ‘ ) = 3/9 = 𝟏/πŸ‘ So, the correct answer is (d)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.