If the letters of the word RAMANUJAN are put in a box and one letter is drawn at random. The probability that the letter is A is

(a) 3/5  (b) 1/2  (c) 3/7   (d) 1/3

Slide67.jpeg

Advertisement

Slide68.jpeg

Advertisement

  1. Class 10
  2. Solutions of Sample Papers for Class 10 Boards

Transcript

Question 37 If the letters of the word RAMANUJAN are put in a box and one letter is drawn at random. The probability that the letter is A is (a) 3/5 (b) 1/2 (c) 3/7 (d) 1/3 The word word RAMANUJAN has 1 R, 3 A, 1 M, 2 N, 1 U, 1 J, Total number of letters = 9 Number times A comes = 3 Thus, Probability that the letter is A = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ก๐‘–๐‘š๐‘’๐‘  ๐ด ๐‘๐‘œ๐‘š๐‘’๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘™๐‘’๐‘ก๐‘ก๐‘’๐‘Ÿ๐‘ ) = 3/9 = ๐Ÿ/๐Ÿ‘ So, the correct answer is (d)

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.