The mid-point of (3p, 4) and (β2, 2q) is (2, 6) . Find the value of p + q
(a) 5Β (b) 6 Β Β Β Β Β (c) 7Β Β Β Β Β Β (d) 8
Last updated at Sept. 8, 2021 by
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Question 19 The mid-point of (3p, 4) and (β2, 2q) is (2, 6) . Find the value of p + q (a) 5 (b) 6 (c) 7 (d) 8 Let point M (2, 6) be Mid-point of A (3p, 4) and B (β2, 2a) Now, Coordinates of mid-point M = ((π₯_1 + π₯_2)/2,(π¦_1 + π¦_2)/2) (2, 6) = ((ππ + (βπ) )/π,(π + ππ)/π) (2, 6) = ((3π β 2)/2,(2π + 4)/2) Comparing x-coordinate 2 = (ππ β π)/π 2 Γ 2 = 3p β 2 4 = 3p β 2 4 + 2 = 3p 6 = 3p 3p = 6 p = 6/3 p = 2 Comparing y-coordinate 6 = (ππ + π)/π 6 Γ 2 = 2q + 4 12 = 2q + 4 12 β 4 = 2q 8 = 2q 2q = 8 q = 8/2 q = 4 Thus, p + q = 2 + 4 = 6 So, the correct answer is (b)
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
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CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
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