What is the value of (tan πœƒ cosec πœƒ) 2   − (sin πœƒ  sec πœƒ)2

(a) −1   (b) 0   (c) 1   (d) 2

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Question 32 What is the value of (tan πœƒ cosec πœƒ)2 βˆ’ (sin πœƒ sec πœƒ)2 (a) βˆ’1 (b) 0 (c) 1 (d) 2 (tan πœƒ cosec πœƒ)2 βˆ’ (sin πœƒ sec πœƒ)2 = (sin⁑θ/cos⁑〖θ γ€— Γ—1/sin⁑〖θ γ€— )^2 βˆ’ (sin⁑〖θ γ€—Γ—1/cos⁑〖θ γ€— )^2 = (1/cos⁑〖θ γ€— )^2 βˆ’ (sin⁑〖θ γ€—/cos⁑〖θ γ€— )^2 = γ€–π¬πžπœγ€—^𝟐 𝜽 βˆ’γ€–π­πšπ§γ€—^𝟐 𝜽 = 1 So, the correct answer is (c) We know that 1 + tan2 ΞΈ = sec2 ΞΈ 1 = sec2 ΞΈ βˆ’ tan2 ΞΈ sec2 ΞΈ βˆ’ tan2 ΞΈ = 1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.