What is the value of (tan 𝜃 cosec 𝜃) 2   − (sin 𝜃  sec 𝜃)2

(a) −1   (b) 0   (c) 1   (d) 2

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Question 32 What is the value of (tan 𝜃 cosec 𝜃)2 − (sin 𝜃 sec 𝜃)2 (a) −1 (b) 0 (c) 1 (d) 2 (tan 𝜃 cosec 𝜃)2 − (sin 𝜃 sec 𝜃)2 = (sin⁡θ/cos⁡〖θ 〗 ×1/sin⁡〖θ 〗 )^2 − (sin⁡〖θ 〗×1/cos⁡〖θ 〗 )^2 = (1/cos⁡〖θ 〗 )^2 − (sin⁡〖θ 〗/cos⁡〖θ 〗 )^2 = 〖𝐬𝐞𝐜〗^𝟐 𝜽 −〖𝐭𝐚𝐧〗^𝟐 𝜽 = 1 So, the correct answer is (c) We know that 1 + tan2 θ = sec2 θ 1 = sec2 θ − tan2 θ sec2 θ − tan2 θ = 1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.