In ∆ABC, ˂B = 90° and BD ꓕ AC. If AC = 9cm and AD = 3 cm then BD is equal to

(a) 2√2cm   (b) 3√2  cm   (c) 2√3  cm   (d) 3 √3 cm

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Question 23 In ∆ABC, ˂B = 90° and BD ꓕ AC. If AC = 9cm and AD = 3 cm then BD is equal to (a) 2√2cm (b) 3√2 cm (c) 2√3 cm (d) 3 √3 cm Let ∠ A = x° In Δ ABC ∠ ACB = 90° − x And, in Δ ABD ∠ ABD = 90° − x For Δ ABD and Δ BCD ∠ ABD = ∠ BCD ∠ BAC = ∠ DAB ∴ Δ ABD ~ Δ BCD Since sides in similar triangle are proportional 𝑨𝑫/𝑩𝑫=𝑩𝑫/𝑪𝑫 3/𝐵𝐷=𝐵𝐷/6 3 × 6 = BD2 18 = BD2 BD2 = 18 BD2 = 9 × 2 BD2 = 32 × 2 BD = 3 × √2 BD = 3 √𝟐 cm So, the correct answer is (b)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.