In ∆ABC, ˂B = 90° and BD ꓕ AC. If AC = 9cm and AD = 3 cm then BD is equal to
(a) 2√2cm (b) 3√2 cm (c) 2√3 cm (d) 3 √3 cm


CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 23 In ∆ABC, ˂B = 90° and BD ꓕ AC. If AC = 9cm and AD = 3 cm then BD is equal to (a) 2√2cm (b) 3√2 cm (c) 2√3 cm (d) 3 √3 cm Let ∠ A = x° In Δ ABC ∠ ACB = 90° − x And, in Δ ABD ∠ ABD = 90° − x For Δ ABD and Δ BCD ∠ ABD = ∠ BCD ∠ BAC = ∠ DAB ∴ Δ ABD ~ Δ BCD Since sides in similar triangle are proportional 𝑨𝑫/𝑩𝑫=𝑩𝑫/𝑪𝑫 3/𝐵𝐷=𝐵𝐷/6 3 × 6 = BD2 18 = BD2 BD2 = 18 BD2 = 9 × 2 BD2 = 32 × 2 BD = 3 × √2 BD = 3 √𝟐 cm So, the correct answer is (b)