Question 26 Given that sin π = π/π, then tan π is equal to (a) π/β(π^2 + π^2 ) (b) π/β(π^2 β π^2 ) (c) π/β(π^2 + π^2 ) (d) π/β(π^2 + π^2 )
Let Ξ ABC be the right angled triangle
Given
sin π = π/π
Since sin π = πΆπππππππ/π―πππππππππ
Therefore,
BC = a, AC = b
Finding side AB
By Pythagoras theorem
AC2 = AB2 + BC2
b2 = AB2 + a2
b2 β a2 = AB2
AB2 = b2 β a2
AB = β(π^πβπ^π )
Now,
tan π = π΅πΆ/π΄π΅
= π/β(π^π β π^π )
So, the correct answer is (d)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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