Question 26 Given that sin π = π/π, then tan π is equal to (a) π/β(π^2 + π^2 ) (b) π/β(π^2 β π^2 ) (c) π/β(π^2 + π^2 ) (d) π/β(π^2 + π^2 )
Let Ξ ABC be the right angled triangle
Given
sin π = π/π
Since sin π = πΆπππππππ/π―πππππππππ
Therefore,
BC = a, AC = b
Finding side AB
By Pythagoras theorem
AC2 = AB2 + BC2
b2 = AB2 + a2
b2 β a2 = AB2
AB2 = b2 β a2
AB = β(π^πβπ^π )
Now,
tan π = π΅πΆ/π΄π΅
= π/β(π^π β π^π )
So, the correct answer is (d)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.