Given that sin πœƒ = a/b, then tan πœƒΒ  is equal to

(a) b/√(a 2 + b 2 )  (b) b/√(b 2 - a 2 )  (c) a/√(a 2 + b 2 )   (d) b/√(b^ 2 + a 2 )

Ques 26 (MCQ) - Given that sin ΞΈ = a/b, then tan ΞΈ is equal to [Video] - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
part 2 - Question 26 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 26 Given that sin πœƒ = π‘Ž/𝑏, then tan πœƒ is equal to (a) 𝑏/√(π‘Ž^2 + 𝑏^2 ) (b) 𝑏/√(𝑏^2 βˆ’ π‘Ž^2 ) (c) π‘Ž/√(π‘Ž^2 + 𝑏^2 ) (d) 𝑏/√(𝑏^2 + π‘Ž^2 ) Let Ξ” ABC be the right angled triangle Given sin πœƒ = 𝒂/𝒃 Since sin πœƒ = π‘Άπ’‘π’‘π’π’”π’Šπ’•π’†/π‘―π’šπ’‘π’π’•π’†π’π’–π’”π’† Therefore, BC = a, AC = b Finding side AB By Pythagoras theorem AC2 = AB2 + BC2 b2 = AB2 + a2 b2 βˆ’ a2 = AB2 AB2 = b2 βˆ’ a2 AB = √(𝒃^πŸβˆ’π’‚^𝟐 ) Now, tan πœƒ = 𝐡𝐢/𝐴𝐡 = 𝒂/√(𝒃^𝟐 βˆ’ 𝒂^𝟐 ) So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo