In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot 𝜃 equals
(a) 3/4 (b) 5/12 (c) 4/3 (d) 12/5
Get live Maths 1-on-1 Classs - Class 6 to 12
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
Question 2 Important
Question 3
Question 4 Important
Question 5
Question 6
Question 7 Important
Question 8
Question 9 Important
Question 10
Question 11 Important
Question 12
Question 13
Question 14 Important You are here
Question 15
Question 16 Important
Question 17
Question 18
Question 19 Important
Question 20 Important
Question 21
Question 22
Question 23 Important
Question 24
Question 25 Important
Question 26 Important
Question 27
Question 28
Question 29 Important
Question 30 Important
Question 31
Question 32 Important
Question 33 Important
Question 34
Question 35
Question 36 Important
Question 37 Important
Question 38
Question 39 Important
Question 40
Question 41 (Case Based Question) Important
Question 42 (Case Based Question)
Question 43 (Case Based Question) Important
Question 44 (Case Based Question) Important
Question 45 (Case Based Question)
Question 46 (Case Based Question) Important
Question 47 (Case Based Question) Important
Question 48 (Case Based Question)
Question 49 (Case Based Question)
Question 50 (Case Based Question) Important
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
Last updated at March 29, 2023 by Teachoo
Get live Maths 1-on-1 Classs - Class 6 to 12
Question 14 In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot 𝜃 equals (a) 3/4 (b) 5/12 (c) 4/3 (d) 12/5 To find cot θ, We need to find AB In right Δ ABD By Pythagoras theorem AB2 = AD2 + BD2 AB2 = 42 + 32 AB2 = 16 + 9 AB2 = 25 AB2 = 52 AB = 5 cm Now, tan 𝜃 = 𝐴𝐵/𝐵𝐶 tan 𝜃 = 5/12 Thus, cot 𝜃 = 𝟏𝟐/𝟓 So, the correct answer is (d)