The fault line 3x + y – 9 = 0 divides the line joining the Country P(1, 3) and Country Q(2, 7) internally in the ratio

(a) 3 : 4   (b) 3 : 2   (c) 2 : 3   (d) 4 : 3

Ques 43 (Case Based) - The fault line 3x + y - 9 = 0 divides line join - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]

part 2 - Question 43 (Case Based Question) - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 43 (Case Based Question) - CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 43 The fault line 3x + y – 9 = 0 divides the line joining the Country P(1, 3) and Country Q(2, 7) internally in the ratio (a) 3 : 4 (b) 3 : 2 (c) 2 : 3 (d) 4 : 3 Using section formula x = (š’ŽšŸ š’™šŸ + š’ŽšŸ š’™šŸ)/(š’ŽšŸ + š’ŽšŸ) x = (š‘˜ Ɨ 2 + 1 Ɨ 1)/(š‘˜ + 1) x = (šŸš’Œ + šŸ)/(š’Œ + šŸ) y = (š’ŽšŸ š’ššŸ + š’ŽšŸ š’ššŸ)/(š’ŽšŸ + š’ŽšŸ) y = (š‘˜ Ɨ 7 + 1 Ɨ 3)/(š‘˜ + 1) y = (šŸ•š’Œ + šŸ‘)/(š’Œ + šŸ) Since point Z lies on line It will satisfy it’s equation Putting values of x and y in equation 3x + y āˆ’ 9 = 0 šŸ‘((šŸš’Œ+ šŸ)/(š’Œ + šŸ))+(šŸ•š’Œ + šŸ‘)/(š’Œ + šŸ) āˆ’ 9 = 0 (3(2š‘˜+ 1))/(š‘˜ + 1)+(7š‘˜ + 3)/(š‘˜ + 1) āˆ’ 9 = 0 (6š‘˜ + 3)/(š‘˜ + 1)+(7š‘˜ + 3)/(š‘˜ + 1) āˆ’ 9 = 0 (6š‘˜ + 3 + 7š‘˜ + 3)/(š‘˜ + 1) āˆ’ 9 = 0 (13š‘˜ + 6)/(š‘˜ + 1) āˆ’ 9 = 0 (13š‘˜ + 6 āˆ’ 9(š‘˜ + 1))/(š‘˜ + 1) = 0 (13š‘˜ + 6 āˆ’ 9š‘˜ āˆ’ 9)/(š‘˜ + 1) = 0 (šŸ’š’Œ āˆ’ šŸ‘)/(š’Œ + šŸ) = 0 4k āˆ’ 3 = 0 4k = 3 k = šŸ‘/šŸ’ ∓ Required ratio is 3 : 4 So, the correct answer is (a)

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