1. Chapter 7 Class 10 Coordinate Geometry (Term 1)
  2. Serial order wise
  3. NCERT Exemplar - MCQ

Question 23 - NCERT Exemplar - MCQ - Chapter 7 Class 10 Coordinate Geometry (Term 1)

Last updated at Aug. 16, 2021 by

If the points A (1, 2), O (0, 0) and C (a, b) are collinear, then

(A) a = b  

(B) a = 2b  

(C) 2a = b  

(D) a = –b

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  1. Chapter 7 Class 10 Coordinate Geometry (Term 1)
  2. Serial order wise

    3. NCERT Exemplar - MCQ

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Transcript

Question 23 If the points A (1, 2), O (0, 0) and C (a, b) are collinear, then (A) a = b (B) a = 2b (C) 2a = b (D) a = –b Since points A, O, C are collinear, they will lie on the same line, i.e. they will not form triangle Therefore, Area of ∆AOC = 0 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] = 0 Here x1 = 1, y1 = 2 x2 = 0, y2 = 0 x3 = a, y3 = b Putting values 𝟏/𝟐 [ 1(0 – b) + 0(b − 2) + a(2 − 0) ] = 0 1 (−b) + 0 + 2a = 0 × 2 −b + 2a = 0 2a = b So, the correct answer is (C)

Chapter 7 Class 10 Coordinate Geometry (Term 1)
Serial order wise

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