Question 13 - NCERT Exemplar - MCQ - Chapter 7 Class 10 Coordinate Geometry

Last updated at August 14, 2026 by

The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is

(A) (0, 0)   (B) (0, 2)   (C) (2, 0)   (D) (–2, 0)

MCQ Class 10 - The point which lies on the perpendicular bisector of - NCERT Exemplar - MCQ

part 2 - Question 13 - NCERT Exemplar - MCQ - Serial order wise - Chapter 7 Class 10 Coordinate Geometry

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Question 13 The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is (A) (0, 0) (B) (0, 2) (C) (2, 0) (D) (–2, 0) Let Line l be the perpendicular bisector of AB And let it intersect AB at point P Since Line l is the perpendicular bisector ∴ Line l ⊥ AB And Line l bisects AB Point P is the mid-point of AB Therefore, Coordinates of Point P = ((𝒙_𝟏 + 𝒙_𝟐)/𝟐,(𝒚_𝟏 + 𝒚_𝟐)/𝟐) = ((−2 + 2)/2,(−5 + 5)/2) = (0/2,0/2) = (0, 0) So, the correct answer is (A)

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