## The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is

## (A) (0, 0) (B) (0, 2) (C) (2, 0) (D) (–2, 0)

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Chapter 7 Class 10 Coordinate Geometry

Serial order wise

Last updated at April 16, 2024 by Teachoo

Question 13 The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is (A) (0, 0) (B) (0, 2) (C) (2, 0) (D) (–2, 0) Let Line l be the perpendicular bisector of AB And let it intersect AB at point P Since Line l is the perpendicular bisector ∴ Line l ⊥ AB And Line l bisects AB Point P is the mid-point of AB Therefore, Coordinates of Point P = ((𝒙_𝟏 + 𝒙_𝟐)/𝟐,(𝒚_𝟏 + 𝒚_𝟐)/𝟐) = ((−2 + 2)/2,(−5 + 5)/2) = (0/2,0/2) = (0, 0) So, the correct answer is (A)