Question 10 - NCERT Exemplar - MCQ - Chapter 7 Class 10 Coordinate Geometry

Last updated at Dec. 16, 2024 by

The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is

(A) 14   (B) 28   (C) 8   (D) 6

 

The Area of a Triangle with vertices A (3, 0), B (7, 0) and C (8, 4) - NCERT Exemplar - MCQ

part 2 - Question 10 - NCERT Exemplar - MCQ - Serial order wise - Chapter 7 Class 10 Coordinate Geometry

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Question 10 The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is (A) 14 (B) 28 (C) 8 (D) 6 Since points are A (3, 0), B (7, 0) and C (8, 4) Here x1 = 3 , y1 = 0 x2 = 7 , y2 = 0 x3 = 8 , y3 = 4 Now, Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] = 1/2 [ 3(0 – 4) + 7(4 – 0) + 8(0 − 0) ] = 1/2 [ 3 × −4 + 7 × 4 + 8 × 0 ] = 1/2 [ −12 + 28 + 0 ] = 1/2 × 16 = 8 square units So, the correct answer is (C)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo