The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is
(A) (0, 1) (B) (0, –1) (C) (–1, 0) (D) (1, 0)
NCERT Exemplar - MCQ
Question 2
Question 3 Important
Question 4 Important
Question 5
Question 6
Question 7
Question 8
Question 9 Important
Question 10 Deleted for CBSE Board 2025 Exams
Question 11
Question 12 Important
Question 13 Important
Question 14 Important You are here
Question 15 Important
Question 16
Question 17 Important
Question 18
Question 19 Important
Question 20
Question 21 Deleted for CBSE Board 2025 Exams
Question 22 Important
Question 23 Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Question 14 The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is (A) (0, 1) (B) (0, –1) (C) (–1, 0) (D) (1, 0) Since ABCD is a parallelogram It’s Diagonals bisect each other Therefore, Mid point of AC = Mid point of BD ((−2 + 8)/2,(3 + 3)/2)=((6 + 𝑥)/2,(7 + 𝑦)/2) (6/2,6/2)=((6 + 𝑥)/2,(7 + 𝑦)/2) Comparing x-coordinate 6/2=(6 + 𝑥)/2 6 = 6 + x x = 0 Comparing y-coordinate 6/2=(7 + 𝑦)/2 6 = 7 + y y = −1 ∴ Coordinates of point D is (0, −1) So, the correct answer is (B)