## The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is

## (A) (0, 1) (B) (0, –1) (C) (–1, 0) (D) (1, 0)

NCERT Exemplar - MCQ

Question 1
Important

Question 2

Question 3 Important

Question 4 Important

Question 5

Question 6

Question 7

Question 8

Question 9 Important

Question 10 Deleted for CBSE Board 2025 Exams

Question 11

Question 12 Important

Question 13 Important

Question 14 Important You are here

Question 15 Important

Question 16

Question 17 Important

Question 18

Question 19 Important

Question 20

Question 21 Deleted for CBSE Board 2025 Exams

Question 22 Important

Question 23 Important Deleted for CBSE Board 2025 Exams

Chapter 7 Class 10 Coordinate Geometry

Serial order wise

Last updated at April 16, 2024 by Teachoo

Question 14 The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is (A) (0, 1) (B) (0, –1) (C) (–1, 0) (D) (1, 0) Since ABCD is a parallelogram It’s Diagonals bisect each other Therefore, Mid point of AC = Mid point of BD ((−2 + 8)/2,(3 + 3)/2)=((6 + 𝑥)/2,(7 + 𝑦)/2) (6/2,6/2)=((6 + 𝑥)/2,(7 + 𝑦)/2) Comparing x-coordinate 6/2=(6 + 𝑥)/2 6 = 6 + x x = 0 Comparing y-coordinate 6/2=(7 + 𝑦)/2 6 = 7 + y y = −1 ∴ Coordinates of point D is (0, −1) So, the correct answer is (B)