Question Rolle’s Theorem: Suppose following three condition hold for function y = f(x): 1. function is defined and continuous on closed interval [a, b]; 2. exists finite derivative f ‘(x) on interval (a, b); 3. f(a) = f(b). then there exists point c(a < c < b) such that f ‘(c) = 0. Based on the above information, answer any four of the following questions.
Question 1 (i) Rolle’s theorem is not applicable for the function f(x) = tan x in [0, 𝜋] because _______. (a) it is not continuous in [0, 𝜋] (b) it is differentiable in (0, 𝜋) (c) f(0) ≠ f(𝜋) (d) f(0) = f(𝜋)
Since tan 𝜋/2 is not defined,
tan x is not continuous at x = 𝜋/2
So, the correct answer is (A)
Question 2 The value of c satisfying Rolle’s theorem for the function g(x) = sin x in [0, 𝜋] is _______. (a) 0 (b) p (c) 𝜋/2 (d) 𝜋/4
According to Rolle’s theorem,
There exists a c ∈ (0, 𝜋) such that
g’(x) = 0
(sin x)’ = 0
cos x = 0
∴ x = 𝝅/𝟐
Thus, value of c = 𝝅/𝟐
So, the correct answer is (C)
Question 3 The value of c satisfying Rolle’s theorem for the function h(x) = cos x in [0, 2𝜋] is _______. (a) 0 (b) 𝜋 (c) 𝜋/2 (d) 3𝜋/2
According to Rolle’s theorem,
There exists a c ∈ (0, 2𝜋) such that
h’(x) = 0
(cos x)’ = 0
−sin x = 0
∴ x = 𝜋
Thus, value of c = 𝜋
So, the correct answer is (B)
Question 4 The value of c satisfying Rolle’s theorem for the function p(x) = sin x + cos x in [0, 𝜋] is _______. (a) 0 (b) 𝜋 (c) 𝜋/4 (d) 𝜋/2
According to Rolle’s theorem,
There exists a c ∈ (0, 𝜋) such that
p’(x) = 0
(sin x + cos x)’ = 0
cos x − sin x = 0
cos x = sin x
∴ x = 𝜋/4
Thus, value of c = 𝜋/4
So, the correct answer is (C)
Question 5 Rolle’s theorem is not applicable for the function f (x) = |x| in [–2, 2] because _______. (a) f (–2) ¹ f(2) (b) f(x) is not continuous in [–2, 2] (c) f(x) is not differentiable in (–2, 2) (d) None of these
We know that
|𝑥| is not differentiable at x = 0.
So, the correct answer is (C)
Made by
Davneet Singh
Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.
Many students prefer Teachoo Black for a smooth, ad-free learning experience.
It looks like you're using AdBlock
Don't be a miser! Join Teachoo Black at ₹19 only to view the ad-free version of Teachoo.
Please login to view more pages. It's free :)
Teachoo gives you a better experience when you're logged in. Please login :)