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Ex 7.4
Ex 7.4, 2 Important Deleted for CBSE Board 2023 Exams
Ex 7.4, 3 Important Deleted for CBSE Board 2023 Exams
Ex 7.4, 4 Important Deleted for CBSE Board 2023 Exams
Ex 7.4, 5 Important Deleted for CBSE Board 2023 Exams
Ex 7.4, 6 Deleted for CBSE Board 2023 Exams You are here
Last updated at Aug. 14, 2018 by Teachoo
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex7.4, 6 Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest. Let the given point be P and line be l We draw two line segments PN & PM such that PM ⊥ MN We have to prove: PM > PN In ΔPNM, ∠P + ∠N + ∠M = 180° ∠P + 90° + ∠M = 180° ∠P + ∠M = 180° – 90° ∠P + ∠M = 90° Since angle can’t be 0 or negative Hence, ∠ M < 90° ∠ M < ∠ N PN < PM ∴ Perpendicular line segment is the shortest Hence proved