Ex 7.4, 3 - Chapter 7 Class 9 Triangles (Term 1)

Transcript

Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved