1. Chapter 7 Class 9 Triangles
  2. Serial order wise
  3. Ex 7.4

Ex 7.4, 3 - Chapter 7 Class 9 Triangles

Last updated at June 18, 2018 by

Ex 7.4, 3 - In figure, ∠B < ∠A and ∠C < ∠D. Show that - Ex 7.4

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
    3. Ex 7.4
    Examples →
Ask Download

Transcript

Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved

Chapter 7 Class 9 Triangles
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.