Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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