Chapter 7 Class 9 Triangles
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Question 3 - Angle opposite to longer side - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by

Ex 7.4, 3 - In figure, ∠B < ∠A and ∠C < ∠D. Show that - Ex 7.4

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Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo