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Question 2 - Angle opposite to longer side - Chapter 7 Class 9 Triangles

Last updated at May 29, 2023 by

Ex 7.4, 2 - Sides AB & AC of ABC are extended to points P, Q - Ex 7.4

Ex 7.4, 2 - Chapter 7 Class 9 Triangles - Part 2

Ex 7.4, 2 - Chapter 7 Class 9 Triangles - Part 3 Ex 7.4, 2 - Chapter 7 Class 9 Triangles - Part 4

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Ex7.4, 2 (Method 1) In the given figure sides AB and AC of ABC are extended to points P and Q respectively. Also, PBC < QCB. Show that AC > AB. Similarly, Now, PBC < QCB A + ACB < A + ABC ACB < ABC AB < AC Thus, AC > AB Hence proved. Ex7.4, 2 (Method 2) In the given figure sides AB and AC of ABC are extended to points P and Q respectively. Also, PBC < QCB. Show that AC > AB. Similarly, Now, PBC < QCB PBC > QCB 180 PBC > 180 QCB

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