![Ex 7.4, 2 - Chapter 7 Class 9 Triangles - Part 2](https://d1avenlh0i1xmr.cloudfront.net/8e2e361b-a49e-4bc2-8d92-9adf3ee20196slide56.jpg)
![Ex 7.4, 2 - Chapter 7 Class 9 Triangles - Part 4](https://d1avenlh0i1xmr.cloudfront.net/ae3ff62f-6192-49cb-93eb-936b6b3cb592slide58.jpg)
Angle opposite to longer side
Last updated at April 16, 2024 by Teachoo
Ex7.4, 2 (Method 1) In the given figure sides AB and AC of ABC are extended to points P and Q respectively. Also, PBC < QCB. Show that AC > AB. Similarly, Now, PBC < QCB A + ACB < A + ABC ACB < ABC AB < AC Thus, AC > AB Hence proved. Ex7.4, 2 (Method 2) In the given figure sides AB and AC of ABC are extended to points P and Q respectively. Also, PBC < QCB. Show that AC > AB. Similarly, Now, PBC < QCB PBC > QCB 180 PBC > 180 QCB