Ex 7.4, 3 - In figure, ∠B < ∠A and ∠C < ∠D. Show that - Ex 7.4

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved

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  • Manas Chauhan's image
    AB and AC of a ∆ABC are produce4 to point E and D  If bisectors BO and CO of angleCBE and angleBCD meet at point O then prove that angle BOC=90-1÷2angleBAC
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