Check sibling questions
Chapter 7 Class 9 Triangles (Term 1)
Serial order wise

Ex 7.3, 4 - BE and CF are two equal altitudes of triangle ABC - RHS

Ex 7.3, 4 - Chapter 7 Class 9 Triangles - Part 2

This video is only available for Teachoo black users


Transcript

Ex 7.3,4 BE and CF are two equal altitudes of a triangle ABC . Using RHS congruence rule , prove that the triangle ABC is isosceles . Given: Given BE is a altitude, So, ∠𝐴EB = ∠CEB= 90∘ Also, CF is a altitude, So, ∠𝐴FC = ∠BFC= 90∘ Also, BE = CF To prove: Δ ABC is isoceles Proof: In ∆BCF and ∆CBE ∠BFC = ∠CEB = 90∘ BC = CB FC = EB ∆ BCF ≅ ∆ CBE ∴ ∠FBC= ∠ECB So, ∠ABC = ∠ACB AB = AC So, ∆ABC is an isosceles triangle

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.