web analytics

Ex 7.3, 4 - BE and CF are two equal altitudes of triangle ABC - Ex 7.3

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
Ask Download

Transcript

Ex 7.3,4 BE and CF are two equal altitudes of a triangle ABC . Using RHS congruence rule , prove that the triangle ABC is isosceles . Given: Given BE is a altitude, So, ∠𝐴EB = ∠CEB= 90∘ Also, CF is a altitude, So, ∠𝐴FC = ∠BFC= 90∘ Also, BE = CF To prove: Δ ABC is isoceles Proof: In ∆BCF and ∆CBE ∠BFC = ∠CEB = 90∘ BC = CB FC = EB ∆ BCF ≅ ∆ CBE ∴ ∠FBC= ∠ECB So, ∠ABC = ∠ACB AB = AC So, ∆ABC is an isosceles triangle

About the Author

CA Maninder Singh's photo - Expert in Practical Accounts, Taxation and Efiling
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
Jail