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Ex 7.3, 3 - Two sides AB, BC & median AM of one triangle ABC - Ex 7.3

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Ex 7.3,3 Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ∆ PQR (see figure ).Show that : ∆ ABM ≅ ∆ PQN Given: AB = PQ BC = QR & AM = PN Also, AM is the median of ∆ ABC So, BM = CM = 1/2 BC Also, PN is the median of ∆ PQR So, QN = RN = 1/2 QR To prove: ∆ ABM ≅ ∆ PQN Proof Since BC = QR 1/2 BC = 1/2 QR BM = QN In ∆ ABM & ∆ PQN AB = PQ AM = PN BM = QN So, ∆ ABM ≅ ∆ PQN Ex 7.3,3 Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ∆ PQR (see figure ).Show that : (ii) ∆ ABC ≅ ∆ PQR From part (i), ∆ ABM ≅ ∆ PQN ∠B= ∠Q In ∆ ABC & ∆ PQR AB = PQ ∠B= ∠Q BC = QR So, ∆ ABC ≅ ∆ PQR

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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