Ex 7.3,3
Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of PQR (see figure ).Show that :
ABM PQN
Given:
AB = PQ
BC = QR
& AM = PN
Also, AM is the median of ABC
So, BM = CM = 1/2 BC
Also, PN is the median of PQR
So, QN = RN = 1/2 QR
To prove: ABM PQN
Proof
Since
BC = QR
1/2 BC = 1/2 QR
BM = QN
In ABM & PQN
AB = PQ
AM = PN
BM = QN
So, ABM PQN
Ex 7.3,3
Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of PQR (see figure ).Show that :
(ii) ABC PQR
From part (i), ABM PQN
B= Q
In ABC & PQR
AB = PQ
B= Q
BC = QR
So, ABC PQR

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.