Chapter 7 Class 9 Triangles (Term 1)

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 7.3,2 AD is an altitude of an isosceles triangle ABC in which AB = AC . Show that (i) AD bisects BC , (ii) AD bisects β π΄. Given: β ABC is an isosceles triangle, So, AB = AC Also, AD is the altitude So, β π΄DC = β π΄DB = 90β To prove: (i) BD = CD & (ii) β π΅π΄π· = β πΆπ΄π· Proof In βADB and βADC β π΄DC = β π΄DB = 90Β° AB = AC AD = AD β΄ β ADB β β ADC Hence, by CPCT β BD = DC and β π΅π΄πΆ = β π·π΄πΆ Hence proved