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Ex 7.1, 7 - AB is a line segment and P is its mid-point - ASA/AAS

Ex 7.1, 7 - Chapter 7 Class 9 Triangles - Part 2

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Ex7.1, 7 AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that BAD = ABE and EPA = DPB (See the given figure). Show that DAP EBP (ii) AD = BE Given: P is the mid point of AB, So, AP = BP BAD = ABE EPA = DPB To prove: (i) DAP EBP (ii) AD = BE Proof: Since EPA = DPB We add DPE both sides EPA + DPE = DPB + DPE DPA = EPB In DAP and EBP, DAP = EBP AP = BP DPA = EPB DAP EBP AD = BE

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.