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Ex 7.1, 7 - AB is a line segment and P is its mid-point - ASA/AAS

Ex 7.1, 7 - Chapter 7 Class 9 Triangles - Part 2


Ex7.1, 7 AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that BAD = ABE and EPA = DPB (See the given figure). Show that DAP EBP (ii) AD = BE Given: P is the mid point of AB, So, AP = BP BAD = ABE EPA = DPB To prove: (i) DAP EBP (ii) AD = BE Proof: Since EPA = DPB We add DPE both sides EPA + DPE = DPB + DPE DPA = EPB In DAP and EBP, DAP = EBP AP = BP DPA = EPB DAP EBP AD = BE

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.