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Ex 7.1, 5 - Chapter 7 Class 9 Triangles (Term 1)

Last updated at May 29, 2018 by

Ex 7.1, 5 - Line l is bisector of angle A and B is any point - ASA/AAS

Ex 7.1, 5 - Chapter 7 Class 9 Triangles - Part 2

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Ex7.1, 5 Line l is the bisector of an angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of A (see the given figure). Show that: (i) APB AQB (ii) BP = BQ or B is equidistant from the arms of A. Given: l is the bisector of A So, PAB = QAB BP & BQ are perpendiculars from B, So, APB = AQB = 90 To prove: (i) APB AQB (ii) BP = BQ Proof: In APB and AQB, APB = AQB PAB = QAB AB = AB APB AQB BP = BQ Hence proved

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