Ex 7.1, 5 - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by

Ex 7.1, 5 - Line l is bisector of angle A and B is any point - Ex 7.1

part 2 - Ex 7.1, 5 - Ex 7.1 - Serial order wise - Chapter 7 Class 9 Triangles

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Ex7.1, 5 Line l is the bisector of an angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of A (see the given figure). Show that: (i) APB AQB (ii) BP = BQ or B is equidistant from the arms of A. Given: l is the bisector of A So, PAB = QAB BP & BQ are perpendiculars from B, So, APB = AQB = 90 To prove: (i) APB AQB (ii) BP = BQ Proof: In APB and AQB, APB = AQB PAB = QAB AB = AB APB AQB BP = BQ Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo