1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise
  3. Ex 7.1

Ex 7.1, 6 - Chapter 7 Class 9 Triangles (Term 1)

Last updated at May 29, 2018 by

Ex 7.1, 6 - In figure, AC = AE, AB = AD and ∠BAD = ∠EAC - SAS

Ex 7.1, 6 - Chapter 7 Class 9 Triangles - Part 2

  1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise

    3. Ex 7.1

    Ex 7.2 →

Transcript

Ex 7.1, 6 In the given figure, AC = AE, AB = AD and BAD = EAC. Show that BC = DE. Given: AC = AE AB = AD BAD = EAC To prove: BC = DE Proof: Given that BAD = EAC BAD + DAC = EAC + DAC BAC = DAE In ABC and ADE, AB = AD BAC = DAE AC = AE ABC ADE BC = DE Hence proved

Chapter 7 Class 9 Triangles (Term 1)
Serial order wise

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