## Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3.

Last updated at Oct. 7, 2019 by Teachoo

Transcript

Question 34 Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3. Given 2x + 3y = 11 x − 2y = −12 From equation (2) x – 2y = –12 x = –12 + 2y Putting value of x in (1) 2x + 3y = 11 2(–12 + 2y) + 3y = 11 –24 + 4y + 3y = 11 –24 + 7y = 11 7y = 11 + 24 7y = 35 y = 35/7 y = 5 Putting y = 5 in (2) x – 2y = –12 x – 2(5) = –12 x – 10 = –12 x = –12 + 10 x = –2 So, x = –2, y = 5 is the solution of the equations Now, we need to value for ‘m’ where y = mx + 3. Putting value of x and y in the equation y = mx + 3 5 = –2m + 3 5 – 3 = –2m 2 = –2m –2m = 2 m = 2/(−2) m = –1

CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic

Paper Summary

Question 1

Question 2 Important

Question 3

Question 4

Question 5 Important

Question 6

Question 7 Important

Question 8

Question 9

Question 10

Question 11

Question 12 (OR 1st question)

Question 12 (OR 2nd question)

Question 13

Question 14 Important

Question 15 Important

Question 16 (OR 1st question) Important

Question 16 (OR 2nd question)

Question 17

Question 18

Question 19

Question 20

Question 21

Question 22 (OR 1st question)

Question 22 (OR 2nd question)

Question 23

Question 24 (OR 1st question) Important

Question 24 (OR 2nd question)

Question 25

Question 26 Important

Question 27

Question 28 (OR 1st question)

Question 28 (OR 2nd question)

Question 29 Important

Question 30 (OR 1st question)

Question 30 (OR 2nd question) Important

Question 31 (OR 1st question)

Question 31 (OR 2nd question) Important

Question 32

Question 33 Important

Question 34 You are here

Question 35

Question 36 (OR 1st question)

Question 36 (OR 2nd question) Important

Question 37

Question 38 (OR 1st question)

Question 38 (OR 2nd question)

Question 39 (OR 1st question) Important

Question 39 (OR 2nd question) Important

Question 40 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.