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Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3.

Question 34 - CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic

Question 34 - CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic - Part 2
Question 34 - CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic - Part 3

 

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Question 34 Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3. Given 2x + 3y = 11 x − 2y = −12 From equation (2) x – 2y = –12 x = –12 + 2y Putting value of x in (1) 2x + 3y = 11 2(–12 + 2y) + 3y = 11 –24 + 4y + 3y = 11 –24 + 7y = 11 7y = 11 + 24 7y = 35 y = 35/7 y = 5 Putting y = 5 in (2) x – 2y = –12 x – 2(5) = –12 x – 10 = –12 x = –12 + 10 x = –2 So, x = –2, y = 5 is the solution of the equations Now, we need to value for ‘m’ where y = mx + 3. Putting value of x and y in the equation y = mx + 3 5 = –2m + 3 5 – 3 = –2m 2 = –2m –2m = 2 m = 2/(−2) m = –1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.