Question 24 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

Evaluate cos 48° cos 42° − sin 48° sin 42°

Evaluate cos 48° cos 42° − sin 48° sin 42° - Teachoo - CBSE Class 10

Note : This is similar to Ex 8.3, 2 (ii) of NCERT – Chapter 8 Class 10

Check the answer here https://www.teachoo.com/1774/531/Ex-8.3--1---Evaluate-(i)-sin-18---cos-72-(ii)-tan-26-cot-64/category/Ex-8.3/

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Question 24 (OR 2nd question) Evaluate cos 48° cos 42° − sin 48° sin 42° cos 48° cos 42° – sin 48° sin 42° = cos (90 – 42)° cos (90 – 48)° – sin 48° sin 42° = sin 42° sin 48° – sin 48° sin 42° = 0 (cos (90 – θ) = sin θ )

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