Last updated at Feb. 25, 2025 by Teachoo
Ex 12.2, 4 Factorise. (iv) ๐ฅ^4 โ ใ"(x โ z)" ใ^4๐ฅ^4 โ ใ"(x โ z)" ใ^4 = ใ(๐ฅ^2)ใ^2 โ [(๐ฅ โ z)^2 ]^2 Using ๐^๐ โ ๐^๐ = (a + b) (a โ b) Here ๐=๐ฅ^2 and b = (๐ฅ โ z)^2 = [๐ฅ^2+(๐ฅ โ z)^2 ] [๐ฅ^2 โ(๐ฅ โ z)^2] Using ๐^๐ โ ๐^๐ = (a + b) (a โ b) Here ๐=๐ฅ and b = (๐ฅ โ z) = [๐ฅ^2+(๐ฅ โ z)^2 ] [๐ฅ+(๐ฅ โ z)] [๐ฅ โ (๐ฅ โ z)] = [๐ฅ^2+(๐ฅ โ z)^2 ] [๐ฅ+ ๐ฅ โ z] [๐ฅ โ๐ฅ+๐ง] = [๐ฅ^2+(๐ฅ โ z)^2 ] [2๐ฅโ z] [๐ง] = [๐^๐+(๐^๐+๐^๐ โ ๐๐๐)][๐๐โ ๐] [๐] = [๐ฅ^2+๐ฅ^2+๐ง^2 โ 2๐ฅ๐ง][2๐ฅโ z] [๐ง] = [ใ2๐ฅใ^2+๐ง^2 โ 2๐ฅ๐ง][2๐ฅโ z] [๐ง] = ๐ณ (๐๐โ๐) (๐๐^๐+๐^๐ โ ๐๐๐) Using ๐^๐ โ ๐^๐ = ๐^2+๐^2 โ 2ab Here ๐=๐ฅ and b = ๐ง
Ex 12.2
Ex 12.2, 1 (ii)
Ex 12.2, 1 (iii) Important
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v)
Ex 12.2, 1 (vi)
Ex 12.2, 1 (vii) Important
Ex 12.2, 1 (viii)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv) Important
Ex 12.2, 2 (v)
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv) Important
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii)
Ex 12.2, 3 (viii) Important
Ex 12.2, 3 (ix)
Ex 12.2, 4 (i)
Ex 12.2, 4 (ii) Important
Ex 12.2, 4 (iii)
Ex 12.2, 4 (iv) Important You are here
Ex 12.2, 4 (v) Important
Ex 12.2, 5 (i)
Ex 12.2, 5 (ii) Important
Ex 12.2, 5 (iii)
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo