Check sibling questions


Transcript

Ex 12.2, 4 Factorise. (iv) ๐‘ฅ^4 โ€“ ใ€–"(x โ€“ z)" ใ€—^4๐‘ฅ^4 โ€“ ใ€–"(x โ€“ z)" ใ€—^4 = ใ€–(๐‘ฅ^2)ใ€—^2 โˆ’ [(๐‘ฅ โˆ’ z)^2 ]^2 Using ๐’‚^๐Ÿ โˆ’ ๐’ƒ^๐Ÿ = (a + b) (a โˆ’ b) Here ๐‘Ž=๐‘ฅ^2 and b = (๐‘ฅ โˆ’ z)^2 = [๐‘ฅ^2+(๐‘ฅ โˆ’ z)^2 ] [๐‘ฅ^2 โˆ’(๐‘ฅ โˆ’ z)^2] Using ๐’‚^๐Ÿ โˆ’ ๐’ƒ^๐Ÿ = (a + b) (a โˆ’ b) Here ๐‘Ž=๐‘ฅ and b = (๐‘ฅ โˆ’ z) = [๐‘ฅ^2+(๐‘ฅ โˆ’ z)^2 ] [๐‘ฅ+(๐‘ฅ โˆ’ z)] [๐‘ฅ โˆ’ (๐‘ฅ โˆ’ z)] = [๐‘ฅ^2+(๐‘ฅ โˆ’ z)^2 ] [๐‘ฅ+ ๐‘ฅ โˆ’ z] [๐‘ฅ โˆ’๐‘ฅ+๐‘ง] = [๐‘ฅ^2+(๐‘ฅ โˆ’ z)^2 ] [2๐‘ฅโˆ’ z] [๐‘ง] = [๐’™^๐Ÿ+(๐’™^๐Ÿ+๐’›^๐Ÿ โˆ’ ๐Ÿ๐’™๐’›)][๐Ÿ๐’™โˆ’ ๐’›] [๐’›] = [๐‘ฅ^2+๐‘ฅ^2+๐‘ง^2 โˆ’ 2๐‘ฅ๐‘ง][2๐‘ฅโˆ’ z] [๐‘ง] = [ใ€–2๐‘ฅใ€—^2+๐‘ง^2 โˆ’ 2๐‘ฅ๐‘ง][2๐‘ฅโˆ’ z] [๐‘ง] = ๐ณ (๐Ÿ๐’™โˆ’๐’›) (๐Ÿ๐’™^๐Ÿ+๐’›^๐Ÿ โˆ’ ๐Ÿ๐’™๐’›) Using ๐’‚^๐Ÿ โˆ’ ๐’ƒ^๐Ÿ = ๐‘Ž^2+๐‘^2 โˆ’ 2ab Here ๐‘Ž=๐‘ฅ and b = ๐‘ง

  1. Chapter 12 Class 8 Factorisation
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo