Ex 12.2, 2 (viii) - Chapter 12 Class 8 Factorisation
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 12.2, 2 Factorise. (viii) 25๐^2 โ 4๐^2 + 28bc โ 49๐^225๐^2 โ 4๐^2 + 28bc โ 49๐^2 = 25๐^2 โ (4๐^2 โ 28bc +49๐^2) = 25๐^2 โ (4๐^๐ + 49๐^๐ + 28bc) = 25๐^2 โ ((2b)2 + (7c)2 โ 2 ร 2b ร 7c) = 25๐^2 โ "(2b โ " ใ"7c)" ใ^๐ = (5a)2 โ "(2b โ " ใ"7c)" ใ^๐ = (5a + (2b โ 7c)) (5a โ (2b โ 7c)) = (5a + 2b โ 7c) (5a โ 2b + 7c) Using ๐^๐ โ ๐^๐ = (๐ฅ + y) (๐ฅ โ y) Here x = 5a and y = 2b โ 7c
Ex 12.2
Ex 12.2, 1 (ii)
Ex 12.2, 1 (iii) Important
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v)
Ex 12.2, 1 (vi)
Ex 12.2, 1 (vii) Important
Ex 12.2, 1 (viii)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv) Important
Ex 12.2, 2 (v)
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important You are here
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv) Important
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii)
Ex 12.2, 3 (viii) Important
Ex 12.2, 3 (ix)
Ex 12.2, 4 (i)
Ex 12.2, 4 (ii) Important
Ex 12.2, 4 (iii)
Ex 12.2, 4 (iv) Important
Ex 12.2, 4 (v) Important
Ex 12.2, 5 (i)
Ex 12.2, 5 (ii) Important
Ex 12.2, 5 (iii)
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo