Ex 12.2, 2 (iv) - Chapter 12 Class 8 Factorisation
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 12.2, 2 Factorise. (iv) 16๐ฅ^5 โ 144๐ฅ^316๐ฅ^5 โ 144๐ฅ^3 = ใ16๐ฅใ^2 ๐ฅ^3โ144๐ฅ^3 Taking ๐ฅ^3 common, = ๐ฅ^3 (16๐ฅ^2โ144) = ๐^๐ ((๐๐)^๐โ(๐๐)^๐ ) Using ๐^๐โ ๐^๐ = (a + b) (a โ b) Here a = 4x and b = 12 = ๐ฅ^3 (4๐ฅ+12) (4๐ฅโ12) = ๐ฅ^3 (4๐ฅ+12) (4๐ฅโ12) Both have 4 as common factor = ๐ฅ^3 ร 4 (๐ฅ + 3) ร 4 (๐ฅ โ 3) = ๐ฅ^3 ร 4 ร 4 (๐ฅ + 3) (๐ฅ โ 3) = 16๐^๐ (๐ + 3) (๐ โ 3)
Ex 12.2
Ex 12.2, 1 (ii)
Ex 12.2, 1 (iii) Important
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v)
Ex 12.2, 1 (vi)
Ex 12.2, 1 (vii) Important
Ex 12.2, 1 (viii)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv) Important You are here
Ex 12.2, 2 (v)
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv) Important
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii)
Ex 12.2, 3 (viii) Important
Ex 12.2, 3 (ix)
Ex 12.2, 4 (i)
Ex 12.2, 4 (ii) Important
Ex 12.2, 4 (iii)
Ex 12.2, 4 (iv) Important
Ex 12.2, 4 (v) Important
Ex 12.2, 5 (i)
Ex 12.2, 5 (ii) Important
Ex 12.2, 5 (iii)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo