Question 3 - Approximations (using Differentiation) - Chapter 6 Class 12 Application of Derivatives
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 3 Find the approximate value of f (5.001), where f (x) = x3 โ 7x2 + 15.Let x = 5 and โ x = 0.001 Given f (x) = x3 โ 7x2 + 15 ๐โ(x) = 3x2 โ 14x Now, โy = fโ(x) โ๐ฅ = (3x2 โ 14x) 0.001 Also, โy = f (x + โx) โ f(x) f(x + โx) = f(x) + โy f (5.001) = x3 โ 7x2 + 15 + (3x2 โ 14x) 0.001 Putting value of x = 5 f (5.001) = 53 โ 7(5)2 + 15 + (0.001) [3"(5)2" โ14(5)] = (125 โ 175 + 15) + (0.001) (5) = โ35 + 0.005 = โ34.995 Hence, the approximate value of f (5.001) is โ34.995
Approximations (using Differentiation)
Question 1 (ii)
Question 1 (iii)
Question 1 (iv)
Question 1 (v) Important
Question 1 (vi)
Question 1 (vii)
Question 1 (viii)
Question 1 (ix)
Question 1 (x)
Question 1 (xi) Important
Question 1 (xii)
Question 1 (xiii)
Question 1 (xiv) Important
Question 1 (xv)
Question 2
Question 3 Important You are here
Question 4
Question 5 Important
Question 6
Question 7
Question 8 (MCQ) Important
Question 9 (MCQ)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo