Question 2 - Approximations (using Differentiation) - Chapter 6 Class 12 Application of Derivatives
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 2 Find the approximate value of f (2.01), where f (x) = 4x2 + 5x + 2.Let x = 2 and โ x = 0.01 Given f(x) = 4x2 + 5x + 2 fโ(x) = 8x + 5 Now, โ๐ฆ = fโ(x) โ x = (8x + 5) 0.01 Also, โy = f (x + โx) โ f(x) f(x + โ x) = f (x) + โ๐ฆ f (2.01) = 4x2 + 5x + 2 + (8x + 5)(0.01) Putting value of x = 2 ๐ (2.01)=4 (2)^2+ 5(2)+2+(0.01)[8(2)+5] = (16+10+2)+(21) (0.01) = 28+0.21 =28.21 Hence, the approximate value of f (2.01) is 28.21
Approximations (using Differentiation)
Question 1 (ii)
Question 1 (iii)
Question 1 (iv)
Question 1 (v) Important
Question 1 (vi)
Question 1 (vii)
Question 1 (viii)
Question 1 (ix)
Question 1 (x)
Question 1 (xi) Important
Question 1 (xii)
Question 1 (xiii)
Question 1 (xiv) Important
Question 1 (xv)
Question 2 You are here
Question 3 Important
Question 4
Question 5 Important
Question 6
Question 7
Question 8 (MCQ) Important
Question 9 (MCQ)
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