Last updated at Dec. 16, 2024 by Teachoo
Ex 10.2, 14 Show that the vector ๐ ฬ + ๐ ฬ + ๐ ฬ is equally inclined to the axes OX, OY and OZ. Let ๐ โ = ๐ ฬ + ๐ ฬ + ๐ ฬ = 1๐ ฬ + 1๐ ฬ + 1๐ ฬ A vector is equally inclined to OX, OY, OZ i.e. X, Y and Z axes respectively, if its direction cosines are equal. Direction ratios of ๐ โ are ๐ = 1, b = 1 , c = 1 Magnitude of ๐ โ = โ(12+12+12) |๐ โ | = โ(1+1+1) = โ3 Direction cosines OF ๐ โ are (๐/|๐ โ | ,๐/|๐ โ | ,๐/|๐ โ | ) = (1/โ3,1/โ3,1/โ3) Since the direction cosines are equal, ๐ โ = ๐ ฬ + ๐ ฬ + ๐ ฬ is equally inclined to OX, OY and OZ
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo