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Ex 10.2, 12 Find the direction cosines of the vector ๐‘– ฬ‚ + 2๐‘— ฬ‚ + 3๐‘˜ ฬ‚ . Let ๐‘Ž โƒ— = ๐‘– ฬ‚ + 2๐‘— ฬ‚ + 3๐‘˜ ฬ‚ = 1๐‘– ฬ‚ + 2๐‘— ฬ‚ + 3๐‘˜ ฬ‚ Direction ratios are a = 1, b = 2, c = 3 Magnitude of ๐‘Ž โƒ— = โˆš(12+2^2+3^2 ) |๐‘Ž โƒ— | = โˆš(1+4+9) = โˆš14 Direction cosines are (๐‘Ž/|๐‘Ž โƒ— | ,๐‘/|๐‘Ž โƒ— | ,๐‘/|๐‘Ž โƒ— | ) Direction cosines of ๐‘Ž โƒ— = (๐Ÿ/โˆš๐Ÿ๐Ÿ’,๐Ÿ/โˆš๐Ÿ๐Ÿ’,๐Ÿ‘/โˆš๐Ÿ๐Ÿ’)

  1. Chapter 10 Class 12 Vector Algebra
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo