Ex 10.3, 13 - Chapter 10 Class 11 Conic Sections
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 10.3, 13 Find the equation for the ellipse that satisfies the given conditions: Ends of major axis ( 3, 0), ends of minor axis (0, 2) We need to find equation of ellipse Given that End of major axis = ( 3, 0) We know that Ends of major axis are the vertices of the ellipse. Vertices of the ellipse = ( 3, 0) Vertices of the ellipse is of the form ( a, 0) So required equation of ellipse is 2 2 + 2 2 = 1 From (1) & (2) a = 3 Also . End of minor axis = (0, b) (0, 2) = (0, b) So, b = 2 Equation of ellipse is 2 2 + 2 2 = 1 Putting values 2 3 2 + 2 2 2 = 1 2 9 + 2 4 = 1
Ex 10.3
Ex 10.3, 2 Important
Ex 10.3, 3
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
Ex 10.3, 7 Important
Ex 10.3, 8
Ex 10.3, 9
Ex 10.3, 10
Ex 10.3, 11 Important
Ex 10.3, 12 Important
Ex 10.3, 13 You are here
Ex 10.3, 14 Important
Ex 10.3, 15
Ex 10.3, 16 Important
Ex 10.3, 17
Ex 10.3, 18 Important
Ex 10.3, 19 Important
Ex 10.3, 20
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo