Check sibling questions


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Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (i) a king of red colour Total number of cards = 52 Total number of kings of red colour = 2 P (getting a king of red colour) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘˜๐‘–๐‘›๐‘” ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘  ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘‘ ๐‘๐‘œ๐‘™๐‘œ๐‘ข๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 2/52 = ๐Ÿ/๐Ÿ๐Ÿ” Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (ii) a face card Total number of cards = 52 Face cards are King, Queen and Jack Each type has 4 cards Total number of face cards = 3 ร— 4 = 12 P (getting a face card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 12/52 = ๐Ÿ‘/๐Ÿ๐Ÿ‘ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iii) A red face card Total number of cards = 52 Face cards are King, Queen and Jack Total number Red of face cards = 6 P (getting a red face card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘‘ ๐‘“๐‘Ž๐‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 6/52 = ๐Ÿ‘/๐Ÿ๐Ÿ” Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iv) the jack of hearts Total number of cards = 52 We have 4 Jack cards Total number of Jack of hearts = 1 P (getting a Jack of hearts) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐ฝ๐‘Ž๐‘๐‘˜ ๐‘œ๐‘“ โ„Ž๐‘’๐‘Ž๐‘Ÿ๐‘ก๐‘  ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = ๐Ÿ/๐Ÿ“๐Ÿ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (v) a spade Total number of cards = 52 We have 4 suits โ€“ Spade, Club, Diamond and Hearts. Total number of spade cards = 13 P (getting a spade card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘๐‘Ž๐‘‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 13/52 = ๐Ÿ/๐Ÿ’ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (vi) the queen of diamonds Total number of cards = 52 We have 4 queen cards Total number of queen of diamonds = 1 P (getting a queen of diamond) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ž๐‘ข๐‘’๐‘’๐‘› ๐‘œ๐‘“ ๐‘‘๐‘–๐‘Ž๐‘š๐‘œ๐‘›๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = ๐Ÿ/๐Ÿ“๐Ÿ

  1. Chapter 14 Class 10 Probability
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo