Question 1 (xv) - Approximations (using Differentiation) - Chapter 6 Class 12 Application of Derivatives
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 1 Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xv) ใ(32.15)ใ^(1/5)Let ๐ฆ=(๐ฅ)^( 1/5) where ๐ฅ=32 & โ๐ฅ=0. 15 Now, ๐ฆ=(๐ฅ)^( 1/5) Differentiating w.r.t.๐ฅ ๐๐ฆ/๐๐ฅ=๐(๐ฅ^( 1/5) )/๐๐ฅ=1/5 ๐ฅ^( 1/5 โ 1) =1/5 ๐ฅ^( (โ 4)/( 5) )=1/(5ใ ๐ฅใ^( 4/5 ) ) Using โ๐ฆ=๐๐ฆ/๐๐ฅ โ๐ฅ โ๐ฆ=1/(5 ใ๐ฅ ใ^(4/5) ) โ๐ฅ Putting Values โ๐ฆ=1/(5(32)^( 4/5) ) ร (0. 15) โ๐ฆ=1/(5(2)^( 5 ร 4/5) ) ร (0. 15) โ๐ฆ=1/(5(2)^( 4) ) ร (0. 15) โ๐ฆ=1/(5 ร 16) ร 0. 15 โ๐ฆ=(0. 15" " )/80 โ๐ฆ=0. 00187 We know that โ๐ฆ=๐(๐ฅ+โ๐ฅ)โ๐(๐ฅ) So, โ๐ฆ=(๐ฅ+โ๐ฅ)^( 1/5)โใ๐ฅ ใ^(1/5) Putting Values 0. 00187=(32+0. 15)^( 1/5)โ(32)^( 1/5) 0. 00187=(32. 15)^( 1/5)โ(2)^(5 ร 1/5 ) 0. 00187=(32. 15)^( 1/5)โ2 0. 00187+2=(32. 15)^( 1/5) 2. 00187=(32. 15)^( 1/5) (32. 15)^( 1/5)=2. 00187 Hence, Approximate Values of (32. 15)^( 1/5) is ๐. ๐๐๐๐๐ Hence, Approximate Values of (32. 15)^( 1/5) is ๐. ๐๐๐๐๐
Approximations (using Differentiation)
Question 1 (ii)
Question 1 (iii)
Question 1 (iv)
Question 1 (v) Important
Question 1 (vi)
Question 1 (vii)
Question 1 (viii)
Question 1 (ix)
Question 1 (x)
Question 1 (xi) Important
Question 1 (xii)
Question 1 (xiii)
Question 1 (xiv) Important
Question 1 (xv) You are here
Question 2
Question 3 Important
Question 4
Question 5 Important
Question 6
Question 7
Question 8 (MCQ) Important
Question 9 (MCQ)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo