# Ex 10.6, 5 (Optional) - Chapter 10 Class 9 Circles (Term 2)

Last updated at Feb. 27, 2019 by Teachoo

Last updated at Feb. 27, 2019 by Teachoo

Transcript

Ex 10.6, 5 (Optional) Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonal. Given: Let ABCD be the rhombus and a circle is drawn taking AB as diameter To Prove: Point E lies on the circle Construction: Let point E be intersection of diagonals AC & BD Proof: We know that Diagonals of a rhombus bisect each other at right angles Hence, ∠AEB = 90° Now, AB is the diameter and it subtends right angle at point E. We know that Diameter subtends 90° at any point on circle. So, point E must lie on the circle Hence Proved

Ex 10.6 (Optional)

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