Ex 12.2, 5 (iii) - Chapter 12 Class 8 Factorisation

Last updated at December 16, 2024 by

Ex 12.2, 5 (iii) - Factorise p^2 + 6p - 16 - Chapter 14 Class 8 - Ex 12.2

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Ex 12.2, 5 Factorise the following expressions. (iii) š‘^2 + 6p ā€“ 16š‘^2 + 6p ā€“ 16 By middle term splitting = š‘^2 āˆ’šŸš’‘+šŸ–š’‘ āˆ’ 16 = (š‘^2āˆ’2š‘)+(8š‘ āˆ’ 1"6") = p (p āˆ’ 2) + 8 (p āˆ’ 2) Taking (p āˆ’ 2) common = (p āˆ’ 2) (p + 8) Splitting the middle term We need to find two numbers whose Sum = 6 Product = āˆ’16 So, we write 6p = āˆ’2p + 8p

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo