Ex 12.2, 5 (ii) - Chapter 12 Class 8 Factorisation

Last updated at August 4, 2026 by

Ex 12.2, 5 (ii) - Factorise q^2 - 10q + 21 - Chapter 14 Class 8 NCERT - Ex 12.2

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Ex 12.2, 5 Factorise the following expressions. (ii) š‘ž^2 ā€“ 10q + 21š‘ž^2 ā€“ 10q + 21 By middle term splitting = š‘ž^2āˆ’šŸ‘š’’āˆ’šŸ•š’’+21 = (š‘ž^2āˆ’3š‘ž)āˆ’(7š‘žāˆ’21) = q (q āˆ’ 3) āˆ’ 7(q āˆ’ 3) Taking (q āˆ’ 3) common, = (q āˆ’ 3) (q āˆ’ 7) Splitting the middle term We need to find two numbers whose Sum = āˆ’10 Product = 21 So, we write āˆ’10q = āˆ’3q āˆ’ 7q

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