Slide33.JPG

Slide34.JPG
Slide35.JPG

  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Example 14 Use the Identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following: (i) 501 Γ— 502 501 Γ— 502 = (500+1)Γ—(500+2) (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 500 , π‘Ž = 1 & 𝑏 = 2 = (500)^2+(1+2)(500)+(1)(2) = 250000+(3Γ—500)+2 = 250000+1500+2 = πŸπŸ“πŸπŸ“πŸŽπŸ Example 14 Use the Identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following: (ii) 95 Γ— 103 95 Γ— 103 = (100βˆ’5)Γ—(100+3) = [100+(βˆ’5)]Γ—[100+3] (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 100 , π‘Ž = βˆ’5 & 𝑏 = 3 = (100)^2+(βˆ’5+2)(100)+(βˆ’5)(3) = 10000+(βˆ’2Γ—100)+(βˆ’15) = 10000βˆ’200βˆ’15 = 1000βˆ’215 = πŸ—πŸ•πŸ–πŸ“

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.